Question 1187262
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I.
P(1) = c(2-1) = c
P(2) = c(4-1) = 3c
P(3) = c(6-1) = 5c<br>
P(1)+P(2)+P(3) = c+3c+5c = 1; 9c=1; c=1/9<br>
I. is FALSE<br>
II.
The expected value is
(1/9)(1)+(3/9)(2)+(5/9)(3) = 22/9 = 2.44 (rounded)<br>
II. is TRUE<br>
III.
I don't know what this part says....<br>