Question 112089
-9- radical 108, over 3(negative nine minus a square root of 108 over 3)
My answer is the square root of 3 times sqr root of 4, is this correct?
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I don't think so; I would do it this way.
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Assume you mean:
{{{(-9 -sqrt(108))/3}}}
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Factor inside the radical to reveal a perfect square (9)
{{{(-9 -sqrt(9*12))/3}}}
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Extract the sqrt of 9
{{{(-9 - 3sqrt(12))/3}}}
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Which is:
{{{(-9)/3}}} - {{{(3sqrt(12))/3}}}
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cancel the 3's and 
{{{-3 - sqrt(12)}}} 
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Factor inside the radical to reveal another perfect square:
{{{-3 - sqrt(4*3)}}} 
:
{{{-3 - 2sqrt(3)}}}