Question 112150
A clean-up project is reducing the concenration of a pollutant in the water supply with an 8% decrease per week. What is the half-life of the concentration of the pollutant? What fraction of the original amount of the pollutant will remain when the project ends after 1 year (52 weeks)? 
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This is the approximate half-life formula: For a quantity decaying exponentially at a rate of P% per time period, the half-life is approximately T(half) = approximately 70/P. This approximation works best for small decay rates and breaks down for decay rates about 15%. 
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T(half) = 70/8 = 8.75 per week
T(half) = 8.75*52 = 455 per year
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Comment: This all seems rather strange but that's the
result using the formula.
Cheers,
Stan H.