Question 1187268
NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)= −4.9t2 squared + 325t + 353.
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Rockets launched by NASA have thrust.
That's a projectile.


Assuming that the rocket will splash down into the ocean, at what time does splashdown occur?
It's when h(t) = 0
h(t)= −4.9t^2 + 325t + 353 = 0
*[invoke solve_quadratic_equation -4.9,325,353]
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 t = 67.395 seconds
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Do NOT include this
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The rocket splashes down after seconds.

How high above sea-level does the rocket get at its peak?


The rocket peaks at meters above sea-level.