Question 1187264
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Given that log2=0.3010, log7=0.845 and log5=0.699
Evaluate log45
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45 = 9*5 = 3*3*5.



THEREFORE,    log(45) = log(3*3*5) = log(3) + log(3) + log(5) = 2*log(3) + log(5).



In this problem,   given  log(7) = 0.845  is  IRRELEVANT.



Log(3)  should be given in order for the solution be possible,  but it is  NOT  GIVEN,   and,   therefore,

the solution  CAN  NOT  be obtained.


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As posed,  given problem is  a   F A K E.