Question 1187084
What is the equation of the circle with center at(0.2) and tangent to the line 
3x-4y=12
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There's a formula for the distance from a point to a line, but I'll work it the "long way."
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3x-4y=12 ---> y = (3/4)x - 3
Slope of the line is 3/4
Slope of lines perpendicular is -4/3
(0,2) is the y intercept ---> y = (-4/3)x + 2
Find the intersection of the 2 lines.
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y = (3/4)x - 3
y = (-4/3)x + 2
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(3/4)x - 3 = (-4/3)x + 2
9x - 36 = -16x + 24
25x = 60
x = 2.4
y = -1.2
Intersection at (2.4,-1.2)
Distance from (0,2) = sqrt(diffy^2 + diffx^2) = sqrt(2.4^2 + 3.2^2) = sqrt(16) = 4
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{{{x^2 + (y-2)^2 = 16}}} is the circle