Question 1186975
<pre>
Instead of doing your problem for you, I'll do one using different numbers which
you can use as a model to do yours by.  Here's the problem I'll do:</pre>
Find the equation of the line passing through the point  (−9,5)  and
perpendicular to the line  y=−27x−623.<pre>
First we find the slope of the line y=−27x−623 by comparing it to y = mx+b,
and we see that the slope m is -27.

The slope of a line perpendicular to a given line has a slope which is the
negative reciprocal of the slope of the given line.  So we take the reciprocal
of -27, which is -1/27, and change its sign.  So the slope of the perpendicular
line is 1/27.  Since it passes through (-9,5), we use to point-slope form which
says the equation of the line through (x<sub>1</sub>,y<sub>1</sub>) and having
slope m is:

{{{y-y[1]}}}{{{""=""}}}{{{m(x^""-x[1])}}}

In this case (x<sub>1</sub>,y<sub>1</sub>) = (-9,5), and m = 1/27

{{{y-(5)}}}{{{""=""}}}{{{(1/27)(x^""-(-9))}}}

{{{y-5}}}{{{""=""}}}{{{(1/27)(x^""+9)}}}

That's in point-slope form.

Now do yours the same way using your numbers.

Edwin</pre>