Question 1186946


{{{x^2+10x+c}}}

to find the {{{c}}} value {{{c=(b/2)^2}}}, divide the coefficient of {{{x}}} by {{{2}}} and square the result

{{{c=(10/2)^2}}}=>{{{c=5^2}}}

{{{x^2+10x+5^2}}}

{{{(x+5)^2}}}