Question 1186838
yes, you got it right

I suggest you to write it this way:


{{{(a^3-27)/(2a^3-18a)}}}


{{{(a^3-3^3)/(2a(a^2-9))}}}


{{{((a - 3) (a^2 + 3 a + 9))/(2a(a-3)(a+3))}}}


{{{(cross((a - 3) )(a^2 + 3 a + 9))/(2a*cross((a-3))(a+3))}}}


{{{(a^2 + 3 a + 9)/(2a(a+3))}}}