Question 1186527
In a standard deck of playing cards, there are 52 total cards.<pre> 
<font color = "red">
A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 
A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦</font>
A♠   2♠   3♠   4♠   5♠   6♠   7♠   8♠  9♠  10♠  J♠  Q♠  K♠  
A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣</pre> 
Half of the cards are red<font color = "red"><pre>
A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 
A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦</font></pre>
and half of the cards are black.<pre>
A♠   2♠   3♠   4♠   5♠   6♠   7♠   8♠  9♠  10♠  J♠  Q♠  K♠  
A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣</pre> 
There are 4 aces to a deck,<pre><font color = "red"><pre>
A♥ 
A♦</font>
A♠   
A♣</pre> 
two of which are red aces.
<font color = "red"><pre>
A♥  
A♦</pre></font>   
What is the probability that a randomly-chosen card from a standard deck of
playing cards will be a red card or an ace?<pre>
It will be one of these 28 cards:<font color = "red"><pre>
A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 
A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦</font>
A♠     
A♣   

out of these 52 cards:

<font color = "red">
 
A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 
A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦</font>
A♠   2♠   3♠   4♠   5♠   6♠   7♠   8♠  9♠  10♠  J♠  Q♠  K♠  
A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣ 

So the probability is '28 out of 52', so we make this fraction: 28/52, and
reduce it to 7/13, which is the answer.</pre></pre></pre></pre>
Explain what the probability you determined in Part A means in terms of the deck
of cards.<pre>
You tell the story of the above in your own words.

Edwin</pre>