Question 1186772


{{{g(r)=r^2-4}}}

a. {{{g(5)}}}=

here you are given that {{{r=5}}}, substitute it in given function

{{{g(5)=5^2-4=25-4=21}}}


b. {{{g(-4)}}}=

{{{r=-4}}}

{{{g(-4)=(-4)^2-4=16-4=12}}}

c. {{{g(0)}}}=

{{{r=0}}}

{{{g(0)=0^2-4=-4}}}