<PRE><B>Question 1186764</B>
Cyclist A travelled 60 km. Cyclist B travels 5 km/hr faster than A and travels the same distance in 2 hours less. Find the speed of each.
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t = 60/r
t-2 = 60/(r+5)
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(60/r) - 2 = 60/(r+5)
(60-2r)/r = 60/(r+5)
60r = (60-2r)*(r+5) = -2r^2 + 50r + 300
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2r^2 - 10r - 300 = 0
r^2 - 5r = 60
r^2 - 5r + 6.25 = 66.25
(r-2.5)^2 = 66.25
r = sqrt(66.25) + 2.5
r =~ 10.6394 km/hr




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