Question 1186695
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If 2^y=10, find the value of 8^(2y-1)
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<pre>
{{{8^(2y-1)}}} = {{{(1/8)*8^(2y)}}} = {{{(1/8)*(8^y)*(8^y)}}} = 


    now replace in this formula {{{8^y}}} by {{{10^3}}}  to get


= {{{(1/8)*1000*1000}}} = {{{1000000/8}}} = 125000.    <U>ANSWER</U>
</pre>

Solved.