Question 1186650
{{{10y^2-8x^2+80x+60y-190=0}}}

{{{10y^2+60y-8x^2+80x-190=0}}}

{{{10(y^2+6y)-8(x^2-10x)=190}}}


For the y's you need to use {{{(6/2)^2=9}}}
and for the x's you need to use {{{(10/2)^2=25}}}.
Add them correspondingly INSIDE the grouping symbols.  And add the same quantities which result from the remultiplications to the right hand side.


{{{10(y^2+6y+9)-8(x^2-10x+25)=190+10*9-8*25}}}


{{{10(y+3)^2-8(x-5)^2=80}}}
but this is not yet finished as an answer.  You should be able to continue and then to finish.