Question 1186514
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Your home is built on a square lot. To add more space to your yard, you purchased 
an additional 8m along the side of the property. The area of the lot is now 345 sq m. 
What are the dimensions of the new lot?
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The initial square lot dimension are x by x meters (where x is unknown value now).

After adding the strip of the width of 8 meters along one side of the lot, its are is 345 sq m. 


The area equation is

    x*(x+8) = 345.


Transform to the standard form quadratic equation

    x^2 + 8x - 345 = 0.


    +--------------------------------------------------+
    |    ALGEBRA HAS ALL NECESSARY TOOLS TO SOLVE IT.  |
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Use the quadratic formula to find the roots.


    {{{x[1,2]}}} = {{{(-8 +- sqrt((-8)^2 -4*(-345)))/2}}} = {{{(-8 + 38)/2}}}.


Reject the negative root and use the positive one  x = {{{(-8 + 38)/2}}} = {{{30/2}}} = 15.


<U>ANSWER</U>.  The dimension of the new lot are  15 meters and  15 + 8 = 23 meters.
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Solved.