Question 1186551
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 An apple falls from a tree that is 28m high. How long does it take for it to hit the ground?
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<pre>
The apple falls with uniform acceleration g = 10 m/s^2  (which is 9.81 m/s^2 rounded).


The formula connecting the distance/(the height) and the time is


    h = {{{(gt^2)/2}}},

or

    28 = {{{(10*t^2)/2}}},


HENCE,  t = {{{sqrt(2h/g)}}} = {{{sqrt((2*28)/10)}}} = {{{sqrt(56/10)}}} = {{{sqrt(5.6)}}} = 2.37 seconds.    <U>ANSWER</U>
</pre>

Solved.


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An apple three of the height 28 m - - - never even heard about such tall apple three.