Question 1186486
.
Mrs Lee bought 20 ducks and chickens for 126 dollars. Each chicken cost 2 dollars less than each duck. 
If she bought 6 more chickens than ducks how much did she pay for each chicken
~~~~~~~~~~~~~~


<pre>
I will solve the problem in two steps.


In  <U>STEP 1</U>,  I will determine the number of chickens (x) and ducks (y).

For it, I write two equations from the condition


    x + y = 20      (1)    (total)

    x - y =  6      (2)    (the difference).


To find x, add two equations


    2x = 26  ---->  x = 26/2 = 13.


Then from equation (2),  y = 20-x = 20-13 = 7.


So, 13 chicken and 7 ducs were bought.




Now in  <U>STEP 2</U>,  I will solve for the price of each chicken (p).


For it, I write the total money equation


    13p + 7*(p+2) = 126.


From this equation


    13p + 7p + 14 = 126

    20p = 126 - 14 = 112.


From this equation,   p = 112/20 = 5 {{{12/20}}} dollars = 5 {{{3/5}}}  dollars = 5.60 dollars = 5 dollars and 60 cents.    <U>ANSWER</U>
</pre>

Solved.