Question 16739
Let x = side of square


Area of square = {{{x^2 = 5.76}}}, where x>0
{{{x = sqrt(5.76) = 2.4}}} cm. 


Perimeter of square = {{{4*x = 9.6}}} cm.


Perimeter of triangle = perimeter of square = 9.6 cm.


R^2 at SCC