Question 1186458
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This kind of "working together" problem is so common that it is worthwhile to remember the simple formula shown by one of the tutors.<br>
If you want to understand the standard formal algebraic method for solving the problem (which leads to that formula), use the method shown by the other tutor.<br>
And for another method for solving this type of problem that many students prefer, you can try this:<br>
Consider the least common multiple of the two given times of 10 days and 12 days, which is 60 days.
In 60 days, Jose could do 60/10=6 of these jobs and Roy could do 60/12=5 of them.
So together in 60 days the two of them could do 11 of the jobs.
And so the amount of time it would take the two of them together to do the one job is 60/11 days.<br>