Question 1186466
<pre>
1.(x+3)(x + 2i)(x - 2i) = 0 has roots -3, -2i, 2i

2.x3-3x2+4x-12=0 has roots 3, -2i, 2i

3.(x+3)(x2+4)=0 has roots -3, -2i, 2i

4. x3+3x2+4x+12=0 doesn't have any rational solutions.

So there are two correct answers, 1 and 3.  They both have solutions -3, -2i, 2i.

Edwin</pre>