<PRE><B>Question 1186434</B>
The price of one pair of pants is $48 and the shirt is sold at 3/4 the price of a pair of pants. Therefore the price of shirt is given by;

48 ⋅ 3/4 = 36
 
Therefore the price of a shirt is $36.

Now let x and y be the number of shirts and pants sold. On Friday 2/3 of the clothing in his shop are sold and he collected $3672. That is;

x ⋅ 36 + y ⋅ 48 = 3672 ⋯⋯⋯[÷12]
         	3x+4y=306  
Now it is also given that 2/5 of the clothing sold were pants. So;
2/5(x + y)=y
2x + 2y = 5y
2x = 5y - 2y
2x = 3y
Applying this in the above equation;
3x + 4y = 306
3x + 4 2x/3 = 306 ⋯⋯⋯⋯[Therefore 2x=3y]
9x+8x/3 = 306
x = 306⋅3/17
= 54
Therefore 3y = 54 ⋅ 2
x = 54⋅2/3
= 36
Therefore 36 pants and 54 shirts were sold on friday.



It is given that Derek sold 2/3 of the clothing in his shop. For T being the total number of cloths in the shop;
2/3(T) = x+y
T = 3/2 (x + y)
= 135
Therefore cloths left on shop will be 1/3  of the cloths. So;
1/3 ⋅ 145 = 45
Therefore 45 cloths will be left unsold.</PRE>