Question 1186411
.
Peter is 36 years old. Peter is twice as old as Jun was when Peter was as old as Jun is now. How old is Jun?
~~~~~~~~~~~~~~~~~~~~~~


<pre>
Let J be the Jun's age now.


How many years ago Peter was as old as Jun is now ? --- ANSWER :  36-J years ago.


How old was Jun then ? --- ANSWER :  J - (36-J)  = 2J-36  years old.


Now we can write the setup equation, as we read the problem


    36 = 2*(2J-36).


Simplify and find J from this equation


    36 = 4J - 72

    36 + 72 = 4J

      108   = 4J

       J    = 108/4 = 27.


<U>ANSWER</U>.  Jun is 27 years old.


<U>CHECK</U>.   Peter was as old as Jun is now 36-27 = 9 years ago.

         9 years ago Jun was 27-9 = 18 years.

         Peter's age now (36) is twice Jun's age then  (9 years ago Jun was 18 years old.

                            ! Correct !
</pre>

Solved.


-----------------


It is a twisted age word problem.


To see many other similar problems solved, look at the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Really-intricate-age-word-problem.lesson>Really intricate age word problems</A>

in this site.



Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic "<U>Age word problems</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.