Question 1186317


Shorter leg = x
Longer leg = 2x + 20
Hypotenuse = 2x + 30


===>  {{{x^2 + (2x+20)^2 = (2x+30)^2}}}  ===> {{{x^2 - 40x - 500 = 0}}}  after expanding some terms and simplifying.

<===> (x-50)(x+10) = 0.  ===> x = 50.  (x = -10 is not acceptable.)

===> The length of the longer leg is 2*50 + 20 = 120 inches.