Question 1186086
1) A pistol that fires a signal flare gives it an initial velocity (muzzle
velocity) of 125 m/s at an angle of 55.00(degrees) above the horizontal. You
can ignore air resistance.
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(a) What is the magnitude of the horizontal and vertical velocity
component of the signal flare?
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Horiz= 125*cos(55)
Vert = 125*sin(55)
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(c) How long does the signal flare stays in the air?
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Using 9.8 m/sec/sec for gravity:
t = 125*sin(55)/9.8 seconds rising, same time falling
---> 125*sin(55)/4.9 seconds =~ 20.897 seconds.
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(b) What is the flare’s maximum height
The average vertical speed is 1/2 the vert component of the launch speed,
= 125*sin(55)/2
Max height = (125*sin(55)/2)*20.897 =~ 1069.86 meters
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 and the distance from its firing point to its landing point?
= (flight time)*125*cos(55)