Question 1186255
it will be x^3=(1/2a)(-b+/- sqrt (b^2-4ac)
think of this as let z=x^3. so the equation becomes 2z^2-3z-8=0
=(1/4)(3+/- sqrt(9+64))
=(1.4)(3+/- sqrt(73)
=2.89, -1.39
the answer is the cube root of each of those, since we solved for x^3/z
x=-1.11, 1.42

{{{graph(300,300,-3,3,-5,5,2x^6-3x^3-8)}}}