Question 1186286

{{{P(x) = x^3 + 5x^2 + 8x }}}.......equal to zero and factor completely


{{{0= x(x^2 + 5x + 8) }}}

{{{0= x(x^2 + 5x + 8) }}}

zeros:

{{{x=0}}}

{{{x^2 + 5x + 8=0}}}.....use quadratic formula

 {{{x = (-5 +- sqrt( 5^2-4*1*8 ))/(2*1) }}}

{{{x = (-5 +- sqrt( 25-32 ))/2 }}}

{{{x = (-5 +- sqrt( -7 ))/2 }}}


{{{x = (-5 +- sqrt(7 )*i)/2 }}}

zeros:  {{{x = (-5 +sqrt(7 )*i)/2 }}}  or  {{{x = (-5 -sqrt(7 )*i)/2 }}}


answer:{{{0}}},{{{ (-5 +sqrt(7 )*i)/2 }}},{{{ (-5 -sqrt(7 )*i)/2 }}}