Question 1186239


Suppose {{{z }}}varies directly with {{{x}}} and inversely with the square of {{{y}}} :

{{{z=kx/y^2}}}


If {{{z=12 }}}when {{{x=4}}} and {{{y=4}}}

{{{12=(k*4)/4^2}}}

{{{12=k/4}}}

{{{k=12*4}}}

{{{k=48}}}


{{{z=48x/y^2}}}


what is {{{z}}} when {{{x=8}}} and {{{y=10}}}?

{{{z=(48*8)/10^2}}}

{{{z=96/25}}}

{{{z=3.84}}}