Question 1186182
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I just solved this problem yesterday night.



See my solution under this link


<A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1186142.html>https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1186142.html</A>


https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1186142.html



Do not miss it with the &nbsp;"solution" &nbsp;by &nbsp;@josgarithmetic, &nbsp;which is presented in &nbsp;TERRIBLE &nbsp;form.




OK, &nbsp;I will copy/paste that my solution here again for your convenience.



<pre>
The remaining trip is  20 - 5 = 15 miles long.

Mike spends  {{{5/20}}} = {{{1/4}}}  of an hour = 15 minutes for the first part of the trip;

hence, he spends 30 - 15 = 15 minutes for the remaining part.



Thus Mike moves remaining part of 15 miles in 15 minutes;

hence, his speed is 1 mile per minute, or 60 miles per hour.    <U>ANSWER</U>
</pre>


Solved and thoroughly explained.