Question 1185943


Geometric Mean ={{{32}}}

{{{a[3]=4}}}
{{{a[1]}}}=?

Solution:

if Geometric Mean of {{{a[1]}}} and {{{a[3]=4}}} is {{{32}}}, we have

{{{32=sqrt(a[1]*a[3])}}}
{{{32=sqrt(a[1]*4)}}}
{{{32=2sqrt(a[1])}}}
{{{16=sqrt(a[1])}}}
{{{a[1]=256}}}