Question 1185959
Using the intercept in graphing, find the vertex and intercept and aketch of S=-16t^2+64r
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You probably mean S = -16t^2 + 64t
Same as y = -16x^2 + 64x
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At x = 0, y = 0
At y = 0, x = 0 and x = 4
That gives you only 2 points, not sufficient to define a parabola.
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You can make a table to generate additional points:
<pre>
  x	 y	
-4.0	-512	
-3.5	-420	
-3.0	-336	
-2.5	-260	
-2.0	-192	
-1.5	-132	
-1.0	-80	
-0.5	-36	
0.0	0	
0.5	28	
1.0	48	
1.5	60	
2.0	64
2.5	60
3.0	48
3.5	28
4.0	0
</pre>
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DL the FREE graph software at
www.padowan.dk
Use Insert, enter -16x^2 + 64x
Pick a color