Question 1185793
combined proportion is (104+48)/(200+100)=152/300, p1=0.52; p2=0.48, pc=0.506667
random samples assumed 
reject Ho if |z| >1.96
z=(p1-p2)/pc(1-pc)((1/200)+(1/100))
=0.04/sqrt[(0.506667*0.493333)(0.015)
=0.04/0.0612
=0.65
fail to reject Ho at the 5 % level. There is no significant difference at the 5% level.