Question 1185675
.
 In tossing 5 coins, how is the probability of getting all combinations of "heads" or "tails" calculated?
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<pre>
In tossing n coins, the probability of getting k "heads" and m "tails",  where k + m = n,  is 


    P = {{{C[n]^k*(1/2)^k*(1/2)^m}}} = {{{C[n]^k*(1/2)^(k+m)}}} = {{{C[n]^k*(1/2)^n}}}.


It is the formula of binomial distribution.


{{{C[n]^k}}}  are the binomial coefficients.
</pre>

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On binomial distribution, see these Internet sources


https://en.wikipedia.org/wiki/Binomial_distribution


https://www.itl.nist.gov/div898/handbook/eda/section3/eda366i.htm




For binomial distribution probability online calculator (free of charge), see this link


https://stattrek.com/online-calculator/binomial.aspx



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If you want to see many solved problems on binomial distribution probability, &nbsp;look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binomial-distribution-manually.lesson>Simple and simplest probability problems on Binomial distribution</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Typical-binomial-distribution-probability-problems.lesson>Typical binomial distribution probability problems</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/How-to-calculate-binomial-probabilities-using-Technology.lesson>How to calculate Binomial probabilities with Technology (using MS Excel)</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binomial-distribution-using-Technology.lesson>Solving problems on Binomial distribution with Technology (using MS Excel)</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binom-distr-with-Technology-%28using-online-solver%29.lesson>Solving problems on Binomial distribution with Technology (using online solver)</A> 

in this site.


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