Question 1185610
x,y,z; first, second, third


{{{system(x+y+z=32,2x-y=z-5,z=y-3x)}}}


From E2 and E3
{{{system(z=2x-y+5,z=-3x+y)}}}
Equating expressions for z
{{{2x-y+5=-3x+y}}}
{{{5x-2y=-5}}}


Using E3 to substitute into E1
{{{x+y+y-3x=32}}}
{{{-2x+2y=32}}}
{{{-x+y=16}}}


Revising the system in two variables:
{{{system(5x-2y=-5,-x+y=16)}}}



That still could be shown as
{{{system(5x-2y=-5,-2x+2y=32)}}}
Add:
{{{3x=27}}}
{{{highlight_green(x=9)}}}
From that, you can solve for y and z.