Question 1185555
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(a) A 7 or an 8 or a 9<br>
4 7's, 4 8's, and 4 9's, so a total of 12.  P=12/52 = 3/13<br>
(b) A spade or a queen or a king<br>
13 spades; 3 queens that are not spades; 3 kings that are not spades -- total 19.  P=19/52<br>
(c) A club or a face card<br>
13 clubs; 3*3=9 face cards that are not clubs -- total 22.  P=22/52 = 11/26<br>
(d) A 9 or a 10 or a spade or a club<br>
4 9's and 4 10's; 11 spades that are neither 9 or 10;  11 clubs that are neither 9 or 10 -- total 30.  P=30/52 = 15/26<br>
OR...<br>
13 spades; 13 clubs; 2 9's that are neither spade not club; 2 10's that are neither spade not club -- total 30.  So again P=30/52 = 15/26.<br>