Question 111772
The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base.  If the perimeter is 29 cm, find the length of one of the equal legs. Solve using algebraic equations.
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(4x-8)+(4x-8)+x=29
9x-16=29
9x=45
x=5
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4(5)-8=20-8=12
:)