<PRE><B>Question 1185459</B>
&lt;br&gt;
The quick look solution:&lt;br&gt;
$800 interest on an $8000 investment is a 10% return.
10% is exactly halfway between 8% and 12%.
Therefore half the total was invested at each rate.&lt;br&gt;
ANSWER: $4000 at 8% and $4000 at 12%.&lt;br&gt;
CHECK: .08(4000)+.12(4000)=320+480=800&lt;br&gt;
A typical formal algebraic solution....&lt;br&gt;
x = amount invested at 12%
8000-x = amount invested at 8%&lt;br&gt;
The total interest was $800:&lt;br&gt;
{{{.12(x)+.08(8000-x)=800}}}&lt;br&gt;
Solve using basic algebra....&lt;br&gt;
</PRE>