Question 1185437
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If a formal algebraic solution is not required, here is a quick an easy way to solve any 2-part mixture problem like this.<br>
(1) All P400,000 invested at 8% would yield P32000 interest; all at 10% would yield P40000 interest; the actual amount of interest was P37000.<br>
(2) Picture the three amounts 32000, 37000, and 40000 on a number line and observe/calculate that 37000 is 5000/8000 = 5/8 of the way from 32000 to 40000.<br>
(3)That means 5/8 of the total was invested at the higher rate.<br>
ANSWER: 5/8 of the P400,000, or P250,000, was invested at 10%; the other P150,000 at 8%<br>
CHECK: .10(250000)+.08(150000)=25000+12000=37000<br>