Question 1185422
the distance between (-5,3) and (5,-3) would be found by using the formula of:


length of a two dimensional line on a graph = square root of ((y2-y1)^2 + (x2-x1)^2)


you assing (x1,y1) to one of the points and (x2,y2) to the other point.


it doesn't matter which is assigned to which.


the length would be the same.


for example:


let(x1,y1) = (-5,3) and let (x2,y2) = (5,-3).


the length is equal to sqrt((x2-x1)^2 + (y2-y1)^2) = sqrt(5--5)^2 + (-3-3)^2) = sqrt(10^2 + (-6)^2) = sqrt(100 + 36) = sqrt(136).


let (x1,y1) = (5,-3) and let (x2,y2) = (-5,3).


the length is equal to sqrt((x2-x1)^2 + (y2-y1)^2) = sqrt(-5-5)^2 + (3--3)^2) = sqrt((-10)^2 + 6^2) = sqrt(100 + 36) = sqrt(136).


sqrt means the square root of.


if you look at the line on a graph, it would look like this.


<img src = "http://theo.x10hosting.com/2021/100103.jpg" >


the line itself is the hypotenuse of the right triangle formed.


the vertical leg is the length of (y2 - y1).


the horizontal leg is the length of (x2 - x1).


the pythagorean formula is used to get the length of the line itself.