Question 1185342
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Prove that (2n+1)^2 - (2n-1)^2 is a multiple of 8 for all positive integer values of n.
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<pre>
    (2n+1)^2 - (2n-1)^2 = (4n^2 + 4n + 1) - (4n^2 - 4n + 1) = 8n,  which is a MULTIPLE of 8 for any integer n.
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Proved, solved and explained.


And completed.