Question 1185287
let x equal the first number, x + 1 equal the second number, x + 2 equal the third number.


you get:


x + (x + 1) + (x + 2) = 63


combine like terms to get 3x + 3 = 63


subtract 3 from both sides of the equation to get:


3x = 60


solve for x to get:


x = 60/3 = 20


the three numbers are 20, 21, and 22.


their sum is 63.