Question 111834
Let x=one integer
x/2=1/2 of one integer
Then x+1=next consecutive integer
(3/5)(x+1)=3/5 of the next consecutive integer

Now we are told that:

(3/5)(x+1)-x/2=3  multiply each term by 10 (LCM)
6(x+1)-5x=30  get rid of parens (distributive law)
6x+6-5x=30  subtract 6 from both sides
6x+6-6-5x=30-6  collect like terms

x=24 on integer

x+1=24+1=25 next consecutive integer

CK

(3/5)*(25)-(1/2)*24=3

15-12=3
3=3


Hope this helps--ptaylor