<PRE><B>Question 1185241</B>
the area is equal to 140 square meters.


area is equal to length * width.


let L equal the length and W equal the width.


you ge t:


L * W = 140


if the length is 4 meters longer than the width, the formula becomes:


(W + 4) * W = 140


simplify to get:


W^2 + 4W = 140


subtract 140 from both sides of the equation to get:


W^2 + 4W - 140 = 0


factor this quadratic equation to get:


(W + 14) * (W - 10) = 0


set each factor equal to 0 and solve for x to get:


W = -14 or W = 10


since W has to be positive, the value of W must be equal to 10.


confirm this is correct by replacing W with 10 in the original equation.


you get (W + 4) * (W) = 120 which becomes:
14 * 10 = 140 
since this is true, the value of W = 10 is confirmed to be good.


your solution is:


the rectangle has a length of 14 and a width of 10.








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