Question 1185233
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The members of a mathematics club agreed to contribute equally to
provide a fund of P240. If there had been 3 more members each would
have paid P4 less than the original agreement. How many members
were present in the club?
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<pre>
Let n be the number of members.


Then each contributes  {{{240/n}}}  pesos.


Had the number of members be (n+3),  each would contribute  {{{240/(n+3)}}}  pesos.


The problem says


    {{{240/n}}} - {{{240/(n+3)}}} = 4  pesos.    (1)


Cancel the factor 4 in both sides


    {{{60/n}}} - {{{60/(n+3)}}} = 1.    (2)


From this point, you may reduce the problem to the quadratic equation, which can be solved by factoring.

Alternatively, you can easily GUESS the solution MENTALLY :  n= 12.


<U>CHECK</U>.  {{{60/12}}} - {{{60/(12+3)}}} = {{{60/12}}} - {{{60/15}}} = 5 - 4 = 1.    ! Equation (2) is held !


<U>ANSWER</U>.  There are 12 members in the club.
</pre>

Solved.