Question 1185162
first do 11z*4z^2=44z^3
then 11z*-3z= -33z^2
and 11z*-4= -44z
then 
-3*4z^2=-12z^2
-3*-3z=9z
-3*-4=12
-
2 terms in the first *3 terms in the second =6 terms altogether.
The first and last are unique. There are two z^2 terms and two z terms.
the answer is 44z^3-45z^2-35z+12

You can add terms only if the variable is the same
so you can take -33z^2 and add only another z^2 term, not a z or z^3 or a constant.  
There is another z^2 term, and it is -12z^2. -33z^2=12z^2=-45 z^2
There are no other constant terms and no other z^3 terms, but there are z terms, -44 and 9. Those may be added.