Question 1185098
A six-sided die is printed with the numbers 1,2,3,5,8 and 13. 
(a) Roll the dice once- what is the probability of getting an even number? 
(b) roll the die twice and add the numbers; what is the probability of getting
an odd sum?
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<pre>
(a)  The probability is the ratio of favorable outputs to the total outputs.


     In question (a), there are 2 favorable outputs against 6 total outputs.


     You can do the rest.




(b)  In case (b), the total number of all possible outputs is 6*6 = 36.


     Of them, favorable are sums of even and odd outputs, and the number of such outputs (pairs) is 2*4 + 4*2 = 16.


     So, the number of total favorable outputs is  16  against total possible outputs 36.


     THEREFORE, the probability in case  (b)  is  P = {{{16/36}}} = {{{4/9}}}.
</pre>

Solved.


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An idea which I want to deliver to you in my post is THIS:


<pre>
    To answer question (b), it is not necessary to calculate all, each and every of 36 possible outputs individually and separately.


    You can evaluate all necessary numbers for the solution in more simple and cheaper way, spending less efforts.
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