Question 1184669
the mean of the sample is 11000
the standard deviation of the sample is 2500
the sample size is 24.
the standard error = standard deviation divide by square root of sample size = 2500 / sqrt(24) = 510.3, rounded to one decimal place.
at 5% significance level, the confidence interval will contain 95% of the area under the normal distribution curve.
the critical z-score for that will be plus or minus 1.96.
your critical raw scores will be based on the z-score formula of:
z = (x - m) / s
for the low z-score, the formula becomes:
-1.96 = (x - 11000) / 510.3.
solve for x to get:
x = -1.96 * 510.3 + 11000 = 9999.8.
for the high z-score, the formula becomes:
1.96 = (x - 11000) / 510.3.
solve for x to get:
x = 1.96 * 510.3 + 11000 = 12000.188.
x, in this case, represents the population mean which is assumed to be between 10,000 and 12,000 at 5% significance level.
i'm not sure if this is what you are looking for, but i couldn't see anything else you might want to find.