Question 1185056
<br>
The difference between the sum of their ages 5 years ago and the sum of their ages 3 years from now is 3*8=24.<br>
A mental path for the first part of the problem is to rewrite the given fraction 13/25 as an equivalent fraction in which the difference between numerator and denominator is 24.  The difference between 13 and 25 is 12, so we can double numerator and denominator: 13/25 = 26/50.<br>
So the sum of their ages 5 years ago was 26 and the sum of their ages 3 years from now is 50.  That means the sum of their ages now is 41.<br>
Geneross's age is the same as Clyde's age 5 years ago, so Geneross is 5 years younger than Clyde.<br>
Clyde is 2 years older than Jeffrey, so Jeffrey is 2 years younger than Clyde.<br>
x = Clyde
x-5 = Geneross
x-2 = Jeffrey<br>
The sum of their current ages is 41:<br>
{{{x+x-5+x-2=41}}}
{{{3x-7=41}}}
{{{3x=48}}}
{{{x=16}}}<br>
Their current ages are
Clyde: x=16
Geneross: x-5=11
Jeffrey: x-2=14<br>
ANSWER: Their ages 10 years from now will be
Clyde: 16+10=26
Geneross: 11+10=21
Jeffrey: 14+10=24<br>