Question 1185030


let angle be {{{alpha}}}
the complement of {{{alpha}}} is {{{90-alpha}}}
the  supplement of {{{alpha}}} is {{{180-alpha}}}

if {{{five}}} times the {{{complement}}} of an angle is {{{two}}} times the angle's supplement plus{{{ 40}}} degrees, we have

{{{5(90-alpha)=2(180-alpha)+40}}}
{{{450-5alpha=360-2alpha+40}}}
{{{450-360-40=5alpha-2alpha}}}
{{{50=3alpha}}}
{{{alpha=50/3}}}
{{{alpha=16.666666}}}

 the measure of the supplement: {{{180-16.66666=163.333333}}}