Question 111832
    {{{1&1/3}}} Start with the given mixed number


    {{{3*1=3}}} Multiply the denominator 3 by the whole number 1 to get 3


    {{{3+1=4}}}. Add 3 to the numerator 1 to get 4. This final result is the new numerator


    {{{4/3}}} Place the new numerator over the same denominator


    So the mixed number {{{1&1/3}}} is equivalent to the improper fraction {{{4/3}}}





Now multiply the base of {{{4/3}}} by the height of {{{4/3}}} (remember these are both equivalent to {{{1&1/3}}}) to get


{{{(4/3)(4/3)=(4*4)/(3*3)=16/9}}}



So the area of the square is {{{16/9}}}