Question 1184989
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When Fidel and Janette were married, his age was 3/2 of her age. If on their
golden wedding anniversary, Fidel’s age will be 8/7 of Janette’s age, how old will
each of them be on their golden anniversary?
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<pre>
Let x be the Janette age at the wedding year.

Then the Fidel's age was  {{{(3/2)*x}}} at this year.


On their golden wedding anniversary, the Janette age will be (x+50) years, while the Fidel's age will be {{{(3/2)*x+ 50}}}.


We have this equation then


    {{{(3/2)*x+50}}} = {{{(8/7)*(x+50)}}}.


To solve it, first multiply both sides by GCD of 14; then simplify


    3*7*x + 700 = 2*8*(x+50)

     21x  + 700 = 16x + 800

     21x - 16x  = 800 - 700

        5x      =    100

         x      =    100/5 = 20.


<U>ANSWER</U>.  At marriage, Janette was 20 years old;  Fidel was  {{{(3/2)*20}}} = 30 years old.
</pre>

Solved.